Find the most general value of θ

Question:

Find the most general value of θ satisfying the equation tan θ = –1 and cos θ = 1/√2

Solution:

According to the question,

We have,

tan θ = -1

And cos θ =1/√2 .

⇒ θ = – π/4

So, we know that,

θ lies in IV quadrant.

θ = 2π – π/4 = 7π/4

So, general solution is θ = 7π/4 + 2 n π, n∈ Z

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