Find the number of terms of the A.P. −12, −9, −6, …, 21.
Question:

Find the number of terms of the A.P. −12, −9, −6, …, 21. If 1 is added to each term of this A.P., then find the sum of all terms of the A.P. thus obtained.

Solution:

First term, $a_{1}=-12$

Common difference, $d=a_{2}-a_{1}=-9-(-12)=3$

$a_{n}=21$

$\Rightarrow a+(n-1) d=21$

$\Rightarrow-12+(n-1) \times 3=21$

$\Rightarrow 3 n=36$

$\Rightarrow n=12$

Therefore, number of terms in the given A.P. is 12.

Now, when 1 is added to each of the 12 terms, the sum will increase by 12.

So, the sum of all terms of the A.P. thus obtained

$=S_{12}+12$

$=\frac{12}{2}[2(-12)+11(3)]+12$

$=6 \times(9)+12$

 

$=66$

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