Question:
Find the solution of the linear equation x+2y = 8 which represents a point on
(i) X-axis
(ii) Y-axis
Solution:
We have, x + 2y = 8 ,..(i)
(i) When the point is on the X-axis, then put y = 0 in Eq. (i), we get
x+2 (0)=8
=> x = 8 Hence, the required point is (8, 0).
(ii) When the point is on the Y-axis, then put x = 0 in Eq. (i), we get
0 + 2y = 8
=> y = 8/2 = 4
Hence, the required point is (0, 4).
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