Find the surface area of a sphere whose volume is 606.375 m3.

Volume of the sphere = 606.375 m3

Then $\frac{4}{3} \pi r^{3}=606.375$

$\Rightarrow r^{3}=\frac{606.375 \times 3 \times 7}{4 \times 22}=144.703$

$\Rightarrow r=5.25 \mathrm{~m}$

$\therefore$ Surface area $=4 \pi r^{2}$

$=4 \times \frac{22}{7} \times 5.25 \times 5.25$

$=346.5 \mathrm{~m}^{2}$