Find the value

Question:

Find the value

$8 a^{3}+27 b^{3}+36 a^{2} b+54 a b^{2}$

Solution:

$=(2 a)^{3}+(3 b)^{3}+3 \times(2 a)^{2} \times 3 b+3 \times 2 a \times(3 b)^{2}$

$=(2 a+3 b)^{3}$

$\left[\therefore a^{3}+b^{3}+3 a^{2} b+3 a b^{2}=(a+b)^{3}\right]$

$=(2 a+3 b)(2 a+3 b)(2 a+3 b)$

$\therefore 8 a^{3}+27 b^{3}+36 a^{2} b+54 a b^{2}$

$=(2 a+3 b)(2 a+3 b)(2 a+3 b)$

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now