Question:
Find the value
$x^{3}+x-3 x^{2}-3$
Solution:
Taking $x$ common in $x^{3}+x$
$=x\left(x^{2}+1\right)-3 x^{2}-3$
Taking $-3$ common in $-3 x^{2}-3$
$=x\left(x^{2}+1\right)-3\left(x^{2}+1\right)$
Now, we take $\left(x^{2}+1\right)$ common
$=\left(x^{2}+1\right)(x-3)$
$\therefore x^{3}+x-3 y^{2}-3=\left(x^{2}+1\right)(x-3)$
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