Find the value
Question:

$\left(4 x^{2}+4 x-3\right)=?$

(a) (2x − 1) (2x − 3)
(b) (2x + 1) (2x − 3)
(c) (2x + 3) (2x − 1)
(d) none of these

 

Solution:

(c) $(2 x+3)(2 x-1)$

$4 x^{2}+4 x-3=4 x^{2}+6 x-2 x-3$

$=2 x(2 x+3)-1(2 x+3)$

$=(2 x+3)(2 x-1)$

 

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