For a gas
Question:

For a gas $\mathrm{C}_{\mathrm{P}}-\mathrm{C}_{\mathrm{V}}=\mathrm{R}$ in a state $\mathrm{P}$ and $\mathrm{C}_{\mathrm{P}}-\mathrm{C}_{\mathrm{V}}=1.10 \mathrm{R}$ in a state $\mathrm{Q}, \mathrm{T}_{\mathrm{P}}$ and $\mathrm{T}_{\mathrm{Q}}$ are the temperatures in two different states $P$ and $Q$ respectively. Then

1. $T_{P}=T_{Q}$

2. $T_{P}<T_{Q}$

3. $T_{P}=0.9 T_{Q}$

4. $T_{P}>T_{Q}$

Correct Option: , 4

Solution:

$\mathrm{C}_{\mathrm{P}}-\mathrm{C}_{\mathrm{V}}=\mathrm{R}$ for ideal gas and gas behaves as ideal gas at high temperature

so $\mathrm{T}_{\mathrm{P}}>\mathrm{T}_{\mathrm{Q}}$