Question:
For a reaction scheme $\mathrm{A} \stackrel{k_{1}}{\longrightarrow} \mathrm{B} \stackrel{k_{2}}{\longrightarrow} \mathrm{C}$, if the rate of formation of $B$ is set to be zero then the concentration of $B$ is given by:
Correct Option: , 4
Solution:
$\mathrm{A} \stackrel{\mathrm{k}_{1}}{\longrightarrow} \mathrm{B} \stackrel{\mathrm{k}_{2}}{\longrightarrow} \mathrm{C}$
$\frac{\mathrm{d}[\mathrm{B}]}{\mathrm{dt}}=\mathrm{k}_{1}[\mathrm{~A}]-\mathrm{k}_{2}[\mathrm{~B}]=0$
$[\mathrm{B}]=\frac{\mathrm{k}_{1}[\mathrm{~A}]}{\mathrm{k}_{2}}$
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