For the equilibrium,

Question:

For the equilibrium, $\mathrm{A}(\mathrm{g}) \rightleftharpoons \mathrm{B}(\mathrm{g}), \Delta \mathrm{H}$ is $-40 \mathrm{~kJ} / \mathrm{mol}$. If the ratio of the activation energies of the forward $\left(\mathrm{E}_{\mathrm{f}}\right)$ and reverse $\left(\mathrm{E}_{\mathrm{b}}\right)$ reactions is $\frac{2}{3}$ then :-

  1. $\mathrm{E}_{\mathrm{f}}=60 \mathrm{~kJ} / \mathrm{mol} ; \mathrm{E}_{\mathrm{b}}=100 \mathrm{~kJ} / \mathrm{mol}$

  2. $\mathrm{E}_{\mathrm{f}}=30 \mathrm{~kJ} / \mathrm{mol} ; \mathrm{E}_{\mathrm{b}}=70 \mathrm{~kJ} / \mathrm{mol}$

  3. $\mathrm{E}_{\mathrm{f}}=80 \mathrm{~kJ} / \mathrm{mol} ; \mathrm{E}_{\mathrm{b}}=120 \mathrm{~kJ} / \mathrm{mol}$

  4. $\mathrm{E}_{\mathrm{f}}=70 \mathrm{~kJ} / \mathrm{mol} ; \mathrm{E}_{\mathrm{b}}=30 \mathrm{~kJ} / \mathrm{mol}$

Correct Option: , 3

Solution:

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