Question:
For what value of $k$, is 3 a zero of the polynomial $2 x^{2}+x+k ?$
Solution:
We know that if $x=\alpha$ is zero polynomial, and then $x-\alpha$ is a factor of $f(x)$
Since 3 is zero of $f(x)$
Therefore $x-3$ is a factor of $f(x)$
Now, we divide $f(x)=2 x^{2}+x+k$ by $g(x)=x-3$ to find the value of $k$
Now, remainder $=0$
$k+21=0$
$k=-21$
Hence, the value of $k$ is $-21$
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