Question:
Form the differential equation of all circles which pass through origin and whose centres lie on y-axis.
Solution:
The equation of circles which pass through the origin and whose centre lies on the y-axis is given by,
(x – 0)2 + (y – a)2 = a2, where (0, a) is the centre
x2 + y2 + a2 – 2ay = a2
$\left(x^{2}-y^{2}\right) \frac{d y}{d x}-2 x y=0$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.