From a solid sphere of mass
By Team eSaral
0
0 Views
Question:

From a solid sphere of mass $\mathrm{M}$ and radius $\mathrm{R}$ a cube of maximum possible volume is cut. Moment of inertia of cube about an axis passing through its centre and perpendicular to one of its faces is:-

  1. $\frac{4 \mathrm{MR}^{2}}{9 \sqrt{3} \pi}$

  2. $\frac{4 \mathrm{MR}^{2}}{3 \sqrt{3} \pi}$

  3. $\frac{\mathrm{MR}^{2}}{32 \sqrt{2} \pi}$

  4. $\frac{\mathrm{MR}^{2}}{16 \sqrt{2} \pi}$

Correct Option: 1

Solution:

Team eSaral
Administrator

Leave a comment

Please enter comment.
Please enter your name.