Question.
Given that $\operatorname{HCF}(306,657)=9$, find $\operatorname{LCM}(306,657)$.
Given that $\operatorname{HCF}(306,657)=9$, find $\operatorname{LCM}(306,657)$.
Solution:
$\operatorname{LCM}(306,657)$
$=\frac{\mathbf{3 0 6} \times \mathbf{6 5 7}}{\mathbf{H C F}(\mathbf{3 0 6}, \mathbf{6 5 7})}=\frac{\mathbf{3 0 6} \times \mathbf{6 5 7}}{\mathbf{9}}=22338$
$\operatorname{LCM}(306,657)$
$=\frac{\mathbf{3 0 6} \times \mathbf{6 5 7}}{\mathbf{H C F}(\mathbf{3 0 6}, \mathbf{6 5 7})}=\frac{\mathbf{3 0 6} \times \mathbf{6 5 7}}{\mathbf{9}}=22338$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.