Hoffmann bromomide degradation of benzamide gives product A,
Question:

Hoffmann bromomide degradation of benzamide gives product $A$, which upon heating with $\mathrm{CHCl}_{3}$ and $\mathrm{NaOH}$ gives product $\mathrm{B}$. The structures of $\mathrm{A}$ and $\mathrm{B}$ are :

Correct Option: , 2

Solution: