Question:
How many five - digit numbers can be formed with the digits 5, 4, 3, 5, 3?
Solution:
To find: Number of 5 - digit numbers that can be formed
2 numbers are of 1 kind, and 2 are of another kind
Total number of permutations $=\frac{5 !}{2 ! 2 !}=30$
30 number can be formed
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