Question:
How many persons can be accommodated in a dining hall of dimensions (20 m × 15 m × 4.5 m), assuming that each person requires 5 m3 of air?
(a) 250
(b) 270
(c) 320
(d) 300
Solution:
(b) 270
Number of persons $=\frac{\text { volume of the hall }}{\text { volume of air required by } 1 \text { person }}$
$=\frac{20 \times 15 \times 4.5}{5}$
$=20 \times 3 \times 4.5$
$=270$
∴ 270 persons can be accommodated.
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