If 9×2 + 25y2 = 181 and xy
Question:

If $9 x^{2}+25 y^{2}=181$ and $x y=-6$, find the value of $3 x+5 y$.

Solution:

We have,

$(3 x+5 y)^{2}=(3 x)^{2}+(5 y)^{2}+2 * 3 x * 5 y$

$\Rightarrow(3 x+5 y)^{2}=9 x^{2}+25 y^{2}+30 x y$

$=181+30(-6) \quad\left[\right.$ Since, $9 x^{2}+25 y^{2}=181$ and $\left.x y=-6\right]$

$\Rightarrow(3 x+5 y)^{2}=1$

$\Rightarrow(3 x+5 y)^{2}=(\pm 1)^{2}$

$\Rightarrow 3 x+5 y=\pm 1$

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