Question:
If a semiconductor photodiode can detect a photon with a maximum wavelength of $400 \mathrm{~nm}$, then its band gap energy is:
Correct Option: , 3
Solution:
$\Delta \mathrm{E}=\frac{\lambda \mathrm{c}}{\lambda \mathrm{e}}=3 . \mathrm{leV}$
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