Question:
If a straight line passing thourgh the point $P(-3,4)$ is such that its intercepted portion between the coordinate axes is bisected at $\mathrm{P}$, then its equation is:
Correct Option: , 4
Solution:
Let the line be $\frac{x}{a}+\frac{y}{b}=1$
$(-3,4)=\left(\frac{\mathrm{a}}{2}, \frac{\mathrm{b}}{2}\right)$
$a=-6, b=8$
equation of line is $4 x-3 y+24=0$
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