If an emitter current is
Question:

If an emitter current is changed by $4 \mathrm{~mA}$, the collector current changes by $3.5 \mathrm{~mA}$. The value of $\beta$ will be :

  1. 7

  2. 0.5

  3. 0.875

  4. 3.5


Correct Option: 1

Solution:

$\mathrm{I}_{\varepsilon}=\mathrm{I}_{\mathrm{C}}+\mathrm{I}_{\mathrm{B}}$

$\Rightarrow \Delta \mathrm{I}_{\varepsilon}=\Delta \mathrm{I}_{\mathrm{C}}+\Delta \mathrm{I}_{\mathrm{B}}$

$4 \mathrm{~mA}=3.5 \mathrm{~mA}+\Delta \mathrm{I}_{\mathrm{B}}$

$\Rightarrow \Delta \mathrm{I}_{\mathrm{B}}=0.5 \mathrm{~mA}$

$\Rightarrow \beta=\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{B}}}$

$\beta=\frac{3.5}{0.5}$

$\Rightarrow \beta=7$

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