If one end of a focal chord of the parabola,

$\because y^{2}=16 x$

$\Rightarrow a=4$

One end of focal of the parabola is at $(1,4)$

$\because \mathrm{y}$ - coordinate of focal chord is $2 a t$

$\therefore 2 a t=4$

$\Rightarrow t=\frac{1}{2}$

Hence, the required length of focal chord

$=a\left(t+\frac{1}{t}\right)^{2}=4 \times\left(2+\frac{1}{2}\right)^{2}=25$