If P(E) = 0.05, then P(not E) =
Question:

If P(E) = 0.05, then P(not E) =

(a) −0.05

(b) 0.5

(c) 0.9

(d) 0.95

Solution:

Given: $P(E)=0.05$

TO FIND: $P(\bar{E})$

CALCULATIONWe know that sum of probability of occurrence of an event and probability of non occurrence of an event is 1. Therefore

$P(E)+P(\bar{E})=1$

$0.05+P(\bar{E})=1$

$P(\bar{E})=1-0.05$

$P(\bar{E})=0.95$

Hence the correct answer is option $(d)$