Question:
If $P$ is a point on the parabola $y=x^{2}+4$ which is closest to the straight line $y=4 x-1$, then the co-ordinates of $\mathrm{P}$ are :
Correct Option: , 4
Solution:
$\left.\frac{d y}{d x}\right|_{p}=4$
$\therefore 2 x_{1}=4$
$\Rightarrow x_{1}=2$
$\therefore$ Point will be $(2,8)$
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