If the angular velocity of earth's spin is increased such that the bodies at the

Question:

If the angular velocity of earth's spin is increased such that the bodies at the equator start floating, the duration of the day would be approximately :

(Take : $\mathrm{g}=10 \mathrm{~ms}^{-2}$, the radius of earth, $\mathrm{R}=6400 \times 10^{3} \mathrm{~m}$, Take $\pi=3.14)$

  1. (1) 60 minutes

  2. (2) does not change

  3. (3) 1200 minutes

  4. (4) 84 minutes


Correct Option: , 4

Solution:

(4)

For objects to float

$\mathrm{mg}=\mathrm{m} \omega^{2} \mathrm{R}$

$\omega=$ angular velocity of earth.

$\mathrm{R}=$ Radius of earth

$\omega=\sqrt{\frac{g}{R}} \ldots(1)$

Duration of day $=\mathrm{T}$

$\mathrm{T}=\frac{2 \pi}{\omega} \ldots(2)$

$\Rightarrow \mathrm{T}=2 \pi \sqrt{\frac{\mathrm{R}}{\mathrm{g}}}$

$=2 \pi \sqrt{\frac{6400 \times 10^{3}}{10}}$

$\Rightarrow \frac{\mathrm{T}}{60}=83.775$ minutes

$\simeq 84$ minutes

 

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