Question:
If the Boolean expression
$(p \oplus q)^{\wedge}(\sim p \odot q)$ is equivalent to $p^{\wedge} q$, where $\oplus, \odot \in\{\wedge, \vee\}$, then the ordered pair $(\oplus, \odot)$ is:
Correct Option: 1
Solution:
$(p \oplus q) \wedge(\sim p \square q) \equiv p \wedge q($ given $)$
from truth table $(\oplus, \square)=(\wedge, \vee)$
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