If the equation x2 + 4x + k = 0 has real and distinct roots, then

Solution:

The given quadric equation is $x^{2}+4 x+k=0$, and roots are real and distinct.

Then find the value of k.

Here, $a=1, b=4$ and, $c=k$

As we know that $D=b^{2}-4 a c$

Putting the value of $a=1, b=4$ and,$c=k$

$=(4)^{2}-4 \times 1 \times k$

$=16-4 k$

The given equation will have real and distinct roots, if $D>0$

$16-4 k>0$

$4 k<16$

$k<\frac{16}{4}$

$<4$

Therefore, the value of $k<4$

Thus, the correct answer is (a)