Question:
If the number of five digit numbers with distinct digits and 2 at the $10^{\text {th }}$ place is $336 \mathrm{k}$, then $\mathrm{k}$ is equal to:
Correct Option: , 4
Solution:
Number of five digit numbers with 2 at $10^{\text {th }}$ place $=8 \times 8 \times 7 \times 6=2688$
$=8 \times 8 \times 7 \times 6=2688$
$\because \quad$ It is given that, number of five digit number with
2 at $10^{\text {th }}$ place $=336 k$
$\therefore \quad 336 k=2688 \Rightarrow k=8$
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