If the point (2, -2) lies on the graph of linear equation,

Question:

If the point (2, -2) lies on the graph of linear equation, 5x + 4y = 4, find the value of k. 

Solution:

It is given that the point (2,-2) lies on the given equation, 5x + ky = 4

Clearly, the given point is the solution of the given equation.

Now, Substituting x = 2 and y = - 2 in the given equation, we get 5x + ky = 4

5 × 2 + (- 2) k = 4

2k = 10 – 4

2k = 6

k = 6/2

k = 3 

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