If the prime factorization of a natural number n is

Since, it is given that 

$n=2^{3} \times 3^{2} \times 5^{2} \times 7$

$n=8 \times 9 \times 25 \times 7$

n=(7 \times 9 \times 2) \times(4 \times 25)

$n=(7 \times 9 \times 2) \times 100$

$n=(7 \times 9 \times 2) \times 100$

$n=12600$

Hence the number of consecutive zeroes are2