If the selling price of 18 oranges is equal to the cost price of 16 oranges,
Question:

If the selling price of 18 oranges is equal to the cost price of 16 oranges, find the loss percent.

Solution:

Let the cost price of one orange be Rs. C, and its selling price be Rs. S

Therefore, $16 \mathrm{C}=18 \mathrm{~S}$

$\mathrm{C}=\frac{18}{16} \mathrm{~S}$

As cost price is more than the selling price,

S. P. $=\left(\frac{100-\text { loss } \%}{100}\right)$ C. P

$\mathrm{S}=\left(\frac{100-\text { loss } \%}{100}\right) \mathrm{C}$

$\frac{\mathrm{S}}{\mathrm{C}}=\left(\frac{100-\text { loss } \%}{100}\right)$

$\frac{16}{18}=\left(\frac{100-\text { loss } \%}{100}\right)$

$\frac{1600}{18}=100-$ loss $\%$

$L$ oss $\%=100-\frac{1600}{18}$

$L$ oss $\%=\frac{1800-1600}{18}$

$=\frac{200}{18}=\frac{100}{9}$

$=11 \frac{1}{9}$

Therefore, the loss percent is $11 \frac{1}{9} \%$.