Question:
If the sum of the first 40 terms of the series, $3+4+8+9+13+14+18+19+\ldots$ is (102)m, then $\mathrm{m}$ is equal to :
Correct Option: 1
Solution:
If the sum of the first 40 terms of the series, $3+4+8+9+13+14+18+19+\ldots$ is (102)m, then $\mathrm{m}$ is equal to :
Correct Option: 1