If three coins are tossed simultaneously, then the probability of getting at least two heads, is
Question:

If three coins are tossed simultaneously, then the probability of getting at least two heads, is

(a) $\frac{1}{4}$

(b) $\frac{3}{8}$

(C) $\frac{1}{2}$

 

(d) $\frac{1}{4}$

Solution:

GIVEN: Three coins are tossed simultaneously.

TO FIND: Probability of getting at least two head.

When three coins are tossed then the outcome will be

TTT, THT, TTH, THH. HTT, HHT, HTH, HHH

Hence total number of outcome is 8.

At least two heads means that, THH, HHT, HTH and HHH are favorable events

Hence total number of favorable outcome is 4

We know that PROBABILITY = 

Hence probability of getting at least two head when three coins are tossed simultaneously is equal to

Hence the correct option is 

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