If three of the six vertices of a regular hexagon are chosen
Question:

If three of the six vertices of a regular hexagon are chosen at random, then the probability that the triangle formed with these chosen vertices is equilateral is :

  1. $\frac{3}{10}$

  2. $\frac{1}{10}$

  3. $\frac{3}{20}$

  4. $\frac{1}{5}$


Correct Option: , 2

Solution:

Only two equilateral tringles are possible $\mathrm{A}_{1} \mathrm{~A}_{3}$

$\mathrm{A}_{5}$ and $\mathrm{A}_{2} \mathrm{~A}_{5} \mathrm{~A}_{6}$

$\frac{2}{6_{C_{2}}}=\frac{2}{20}=\frac{1}{10}$

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