If three six faced die each marked with numbers 1 to 6 on six faces,
Question:

If three six faced die each marked with numbers 1 to 6 on six faces, are thrown find the total number of possible outcomes.

Solution:

Number of possible outcomes on one dice = 6   {1,2,3,4,5,6}

Number of possible outcomes on both the other two dice = 6

$\therefore$ Total number of outcomes when three dice are thrown $=6 \times 6 \times 6=216$

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