If two straight lines intersect each other, prove that the ray opposite to the bisector of one of the angles thus

Solution:

Let AB and CD intersect at a point O

Also, let us draw the bisector OP of AOC

Therefore,

AOP = POC ... (i)

Also, let us extend OP to Q.

We need to show that, OQ bisects BOD

Let us assume that OQ bisects BOD, now we shall prove that POQ is a line.

We know that,

AOC and DOB are vertically opposite angles. Therefore, these must be equal,

that is: AOC = DOB  .... (ii)

AOP and BOQ are vertically opposite angles.

Therefore, AOP = BOQ

Similarly, POC = DOQ

We know that: AOP + AOD + DOQ + POC + BOC + BOQ = 360°

2AOP + AOD + 2D0Q + BOC = 360°

2AOP + 2AOD + 2DOQ = 360°

2(AOP + AOD + DOQ) = 360°

AOP + AOD +DOQ = 360/2

AOP + AOD + DOQ = I 80°

Thus, POQ is a straight line.

Hence our assumption is correct. That is,

We can say that if the two straight lines intersect each other, then the ray opposite to the bisector of one of the angles thus formed bisects the vertically opposite angles.