Question:
If x = 3k + 2 and y = 2k – 1 is a solution of the equation 4x – 3y + 1 = 0, find the value of k.
Solution:
Given: 4x – 3y + 1 = 0 .....(1)
x = 3k + 2 and y = 2k – 1
Putting these values in the equation (1) we get
$4(3 k+2)-3(2 k-1)+1=0$
$\Rightarrow 12 k+8-6 k+3+1=0$
$\Rightarrow 6 k+12=0$
$\Rightarrow k+2=0$
$\Rightarrow k=-2$
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