In a circket match, a batsman hits a boundary 6 times out of 30 balls he plays
Question:

In a circket match, a batsman hits a boundary 6 times out of 30 balls he plays. Find the probability that he did not hit a boundary.

Solution:

Number of balls played by the batsman = 30

Number of balls in which he hits boundaries = 6

∴ Number of balls in which he did not hit a boundary = 30 − 6 = 24

$P($ Batsman did not hit a boundary $)=\frac{\text { Number of balls in which he did not hit a boundary }}{\text { Number of balls played by the batsman }}=\frac{24}{30}=\frac{4}{5}$

Thus, the probability that he did not hit a boundary is $\frac{4}{5}$.

 

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