In a class of 60 students, 25 students play cricket and 20 students play tennis and 10 students play both the games.

Let ⋃ denote the universal set

Let C denote the set of students playing circket

Let T denote the set of students playing tennis

n(⋃) = 60, n(C) = 25, n(T) = 20

n(C⋂T) = 10

Then n(C⋃T)' = n(⋃) – n(C⋃T)

n(⋃) – [n(C) + n(T) – n(C⋂T)]

= 60 – [25 + 20 – 10]

= 60 – [45 – 10]

= 60 – 35

n(C⋃T)' = 25

Hence, the number of students who play neither crickets nor tennis is 25

Hence, the correct answer is option B.