In a single throw of two coins, find the probability of getting

The outcomes when two coins are tossed are HH, HT, TH and TT.

i.e., total no. of possible outcomes = 4

(i) Getting both tails means TT.

Number of outcomes with two tails = 1

$\therefore \mathrm{P}_{\text {(both tails) }}=\frac{1}{4}$

(ii) Getting at least 1 tail means $H T, T H$ and $T T$.

With at least one tail, total number of outcomes $=3$

$\therefore \mathrm{P}_{\text {(at least } 1 \text { tail) }}=\frac{3}{4}$

(iii) Getting at most 1 tail means HH, HT and TH.

The number of outcomes for at most 1 tail $=3$

$\therefore \mathrm{P}_{(\text {at most } 1 \text { tail })}=\frac{3}{4}$