In an equilateral triangle $A B C$ if $A D \perp B C$, then $A D^{2}=$
(a) $\mathrm{CD}^{2}$
(b) $2 \mathrm{CD}^{2}$
(c) $3 \mathrm{CD}^{2}$
(d) $4 \mathrm{CD}^{2}$
In an equilateral $\triangle \mathrm{ABC}, \mathrm{AD} \perp \mathrm{BC}$.
In ΔADC, applying Pythagoras theorem, we get
$\mathrm{AC}^{2}=\mathrm{AD}^{2}+\mathrm{DC}^{2}$
$\mathrm{BC}^{2}=\mathrm{AD}^{2}+\mathrm{DC}^{2}(\because \mathrm{AC}=\mathrm{BC})$
$(2 \mathrm{DC})^{2}=\mathrm{AD}^{2}+\mathrm{DC}^{2}(\because \mathrm{BC}=2 \mathrm{DC})$
$4 D C^{2}=A D^{2}+D C^{2}$
$3 \mathrm{DC}^{2}=\mathrm{AD}^{2}$
$3 \mathrm{CD}^{2}=\mathrm{AD}^{2}$
Hence, the correct option is (c).
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.