Question:
In figure, It is given that AB = CD and AD = BC. Prove that ΔADC ≅ ΔCBA.
Solution:
Given that in the figure AB = CD and AD = BC.
We have to prove ΔADC ≅ ΔCBA
Now,
Consider ΔADC and ΔCBA.
We have
AB = CD [Given]
BC = AD [Given]
And AC = AC [Common side]
So, by SSS congruence criterion, we have
ΔADC ≅ ΔCBA
Hence proved
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