Question.
In Milikan's experiment, static electric charge on the oil drops has been obtained by shining X-rays. If the static electric charge on the oil drop is $-1.282 \times 10^{-18} \mathrm{C}$, calculate the number of electrons present on it.
In Milikan's experiment, static electric charge on the oil drops has been obtained by shining X-rays. If the static electric charge on the oil drop is $-1.282 \times 10^{-18} \mathrm{C}$, calculate the number of electrons present on it.
Solution:
Charge on the oil drop $=1.282 \times 10^{-18} \mathrm{C}$
Charge on one electron $=1.6022 \times 10^{-19} \mathrm{C}$
Number of electrons present on the oil drop
$=\frac{1.282 \times 10^{-18} \mathrm{C}}{1.6022 \times 10^{-19} \mathrm{C}}$
$=0.8001 \times 10^{1}$
$=8.0$
Charge on the oil drop $=1.282 \times 10^{-18} \mathrm{C}$
Charge on one electron $=1.6022 \times 10^{-19} \mathrm{C}$
Number of electrons present on the oil drop
$=\frac{1.282 \times 10^{-18} \mathrm{C}}{1.6022 \times 10^{-19} \mathrm{C}}$
$=0.8001 \times 10^{1}$
$=8.0$
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