Question:
In Q. No. 1, The probability that the digit is even is
(a) $\frac{4}{9}$
(b) $\frac{5}{9}$
(c) $\frac{1}{9}$
(d) $\frac{2}{3}$
Solution:
GIVEN: digits are chosen from 1, 2, 3, 4, 5, 6, 7, 8, 9 are placed in a box and mixed thoroughly. One digit is picked at random.
TO FIND: Probability of getting an even digit
Total number of digits is 9
Digits that are even number are 2, 4, 6, and 8
Total number of even digits is 4.
We know that PROBABILITY = 
Hence probability of getting an even digit is 
Hence the correct option is 
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.