In the given figure, O is the centre of a circle. Then, ∠OAB = ?
Question:

In the given figure, O is the centre of a circle. Then, OAB = ?
(a) 50°

(b) 60°
(c) 55°
(d) 65°

Solution:

(d) 65°
We have:
OA = OB (Radii of a circle)
Let  OAB ∠ OBA = x°
In Δ OAB, we have:
x° + x° + 50° = 180°   (Angle sum property of a triangle)
⇒ 2x° = (180° – 50°) = 130°

$\Rightarrow x=\left(\frac{130}{2}\right)^{\circ}=65^{\circ}$

Hence, OAB = 65°

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