In the given figure, PA and PB are tangents from an external point P
Question:

In the given figure, PA and PB are tangents from an external point P to a circle with centre OLN touches the circle at M. Prove that PL + LM = PN + MN.

Solution:

The figure given in the question

From the property of tangents we know that the length of two tangents drawn from an external point will we be equal. Hence we have,

PA = PB

PL + LA = PN + NB …… (1)

Again from the same property of tangents we have,

LA = LM (where L is the common external point for tangents LA and LM)

NB = MN (where N is the common external point for tangents NB and MN)

Substituting LM and MN in place of LA and NB in equation (1), we have

PL + LM = PN + MN

Thus we have proved.

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