In the given figure, two rays BD and CE intersect at a point A. The side BC of ∆ABC have been produced on both sides to points F and G respectively. If ∠ABF = x°, ∠ACG = y° and ∠DAE = z° then z = ?
(a) x + y – 180
(b) x + y + 180
(c) 180 – (x + y)
(d) x + y + 360°
In the given figure, ∠ABF + ∠ABC = 180° (Linear pair of angles)
∴ x° + ∠ABC = 180°
⇒ ∠ABC = 180° − x° .....(1)
Also, ∠ACG + ∠ACB = 180° (Linear pair of angles)
∴ y° + ∠ACB = 180°
⇒ ∠ACB = 180° − y° .....(2)
Also, ∠BAC = ∠DAE = z° .....(3) (Vertically opposite angles)
In ∆ABC,
∠BAC + ∠ABC + ∠ACB = 180° (Angle sum property)
∴ z° + 180° − x° + 180° − y° = 180° [Using (1), (2) and (3)]
⇒ z = x + y − 180
Hence, the correct answer is option (a)
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