In the reported figure,
Question:

In the reported figure, heat energy absorbed by a system in going through a cyclic process is_____ $\pi \mathrm{J}$.

Solution:

For complete cyclic process

$\Delta \mathrm{U}=0$

$\therefore$ from $\Delta Q=\Delta U+W$

$=0+\mathrm{W}$

$\Delta \mathrm{Q}=\mathrm{W}$

$=$ Area

$=\pi \mathrm{r}_{1} \cdot \mathrm{r}_{2}$

$=\pi \times\left(10 \times 10^{3}\right) \times\left(10 \times 10^{-3}\right)$

$\Delta \mathrm{Q}=100 \pi$

$\therefore$ Ans. $=100$