Question:
In the reported figure, heat energy absorbed by a system in going through a cyclic process is_____ $\pi \mathrm{J}$.
Solution:
For complete cyclic process
$\Delta \mathrm{U}=0$
$\therefore$ from $\Delta Q=\Delta U+W$
$=0+\mathrm{W}$
$\Delta \mathrm{Q}=\mathrm{W}$
$=$ Area
$=\pi \mathrm{r}_{1} \cdot \mathrm{r}_{2}$
$=\pi \times\left(10 \times 10^{3}\right) \times\left(10 \times 10^{-3}\right)$
$\Delta \mathrm{Q}=100 \pi$
$\therefore$ Ans. $=100$
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