It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992.
Question:

It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?

Solution:

Probability that two students are not having same birthday $P(\overline{\mathrm{E}})=0.992$

Probability that two students are having same birthday $P(E)=1-P(\bar{E})$

$=1-0.992$

$=0.008$

 

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