Let F1 (A,B,C) =

Question:

Let $F_{1}(A, B, C)=(A \wedge \sim B) \vee[\sim C \wedge(A \vee B)] \vee \sim A$ and $F_{2}(A, B)=(A \vee B) \vee(B \rightarrow \sim A)$ be two logical expressions.

Then:

  1. (1) $\mathrm{F}_{1}$ is not a tautology but $\mathrm{F}_{2}$ is a tautology

  2. (2) $\mathrm{F}_{1}$ is a tautology but $\mathrm{F}_{2}$ is not a tautology

  3. (3) $\mathrm{F}_{1}$ and $\mathrm{F}_{2}$ both area tautologies

  4. (4) Both $\mathrm{F}_{1}$ and $\mathrm{F}_{2}$ are not tautologies


Correct Option: 1

Solution:

Truth table for $\mathrm{F}_{1}$

Not a tautology

Truth table for $\mathrm{F}_{2}$

$\mathrm{F}_{1}$ not shows tautology and $\mathrm{F}_{2}$ shows tautology

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now